∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

Let a triangle ABC AB=14, BC=13, AC=15 cm. If AD and BE are angle

∆ ABC is isosceles with AB AC = 7.5 cm and BC = 9 cm (Fig). The

Δ ABC is an isosceles triangle with AB = AC = 13 cm. The length of

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

Triangle ABC is isosceles with AB = AC = 7.5cm and BC=9cm. The

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

Ex 9.1, 8 - ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm

ΔABC is isosceles with AB=AC=7cm and BC=9cm. The height AD from A

Fig 11.25 Fig 11.26 AABC is isosceles with AB=AC = 7.5 cm and BC

Δ ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height

Δ ABC is isosceles with AB=AC=7.5 cm and BC = 9 cm Figure. The